My favourite Java puzzler 2 + 1 = 4 !!

Here's  my current favourite Java puzzler.

How can you get your code to do this?

Integer b = 2;
Integer c = 1;

System.out.println("b+c : " + (b+c) ); // output: 'b+c : 4' !!

There are no tricks with Sytem.out.println() i.e. you would be able to see the same value in a debugger.

Clue: You need to add a few lines of code somewhere before this in your program.

Scroll down for the solution.
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public static void main(String... args)throws Exception{
        Integer a = 2;

        Field valField = a.getClass().getDeclaredField("value");
        valField.setAccessible(true);
        valField.setInt(a, 3);

        Integer b = 2;
        Integer c = 1;

        System.out.println("b+c : " + (b+c) ); // b+c : 4
}

As you can see (and I would encourage you to go to the source code for Integer) 
there is a static cache (look for the Inner class IntegerCache) where the value of the 
Integer is mapped to its corresponding int value.  The cache will store all numbers 
from -128 to 127 although you can tune this using the property  
java.lang.Integer.IntegerCache.high.